設三角形ABC的三邊長為a,b,c且5a^2+5b^2+5c^2-6ac-8bc=0, 則三角形ABC為何種三角形?為什麼呀?請詳解原連結 過程如下, 請參考5a^2+5b^2+5c^-6ac-8bc=0(按ac, bc分組)(5a^2-6ac+_____)+(5b^2-8bc+______)+5c^2=0(準備配方)(a^2-6/5ac+_____)+(b^2-8/5bc+______)+c^2=0(a^2-6/5ac+9/25c^2)+(b^2-8/5bc+16/25c^2)=0(a-3/5c)^2+(b-4/5c)^2=0得a=3/5c, b=4/5ca:b:c=3/5c:4/5c:c=3:4:5 答:直角...