1. It is given that Q(5,k) is the vertex of the graph of the function y=-x^2+10x-17.Find the maximum value of the function2. It is given that P(h,6) us the vertex if the graph of the function y=x^2-6x+15(a). Find the value of h.(b). Find the axis of symmetry of the graph 原連結1. y= -x^2+10x-17= -(x-5)^2+8, vertex(5,8)=Q(5,k), k=82.y=x^2-6x+15=(x-3)^2+6, (a)vertex(3,6)=P(h,6), h=3 (b)the axis of symmetry of the graph: x-3=0ps. symmetry<> symmery...